SE250:lab-1:kkan048
got trouble to login Linix. Used window MVS to develop program.
http://www.cplusplus.com/reference/clibrary/ctime/clock.html
Some info about function "clock".
CLOCKS_PER_SEC specifies the relation between a clock tick and a second (clock ticks per second).
clock() return the current clock ticks but it is not a value of time.
clock_t is variable defined in <ctime>.
int main()
{
clock_t start_clock_t; clock_t end_clock_t; int n; int a; clock_t time_elapsed_t; start_clock_t=clock(); for (n=0; n<100000000; n++) { } end_clock_t=clock(); time_elapsed_t =(end_clock_t - start_clock_t); printf ("%ld",time_elapsed_t); return 0;
}
this is the code to test the clock ticks in the addition. it is about 220.
When we add an addition in the for lop.
for (n=0; n<100000000; n++) { a++ }
clock ticks is not much different.
When we change the variable to double.
the clock ticks increase 4 times.
The mean time usage in the for loops is comparing n and the end loop condition.
i want the addition become a mean time usage in the for loop. I try to decrease the comparing times.
#include <stdio.h> #include <time.h> int main() { clock_t start_clock_t; clock_t end_clock_t; int n; int a; clock_t time_elapsed_t; start_clock_t=clock(); a=0; for (n=0; n<10000000; n++) { a++; a++; a++; a++; a++; a++; a++; a++; a++; a++;
} end_clock_t=clock(); time_elapsed_t =(end_clock_t - start_clock_t); printf ("%ld",time_elapsed_t); return 0;
}
the clock ticks decrease to about 188. In second version,5 times more addition command had been done.
i guess the best way to test the time of addition is copy and paste 10000000 times "a++" in the main.c . So pure machine code of addition can run for test. And get the clock ticks number.
The for loops include the compare command which makes the time measurement difficult. I think i can't get answer using for loops