SE250:lab-2:hals016

Task 1

The output for Task 1 was the same (size of pointer) regardless of the different types (short,double,float,integer,long).

Lab machine

ip = 4
ip2 = 4
ip3 = 4
ip4 = 4
ip5 = 4
ip6 = 4

Even more surprising is that the Linux Server has exactly the same values as the lab machine Linux server

ip = 4
ip2 = 4
ip3 = 4
ip4 = 4
ip5 = 4
ip6 = 4

I conclude that I do not know what is going on, or why.

Task 2 + 3

In Task 2 the output varied without an obvious logical pattern.

The "(long)(&x) - (long)(&y)" resulted in 2 memory addresses that are quite close to each other.

longx longy
&x = 0x22ccc4, &y = 0x22ccc0, diff = 4

The "(long)(&x - &y)" produced numbers that are quite puzzling.

long(x-y)
*char0*&x = 0x22ccc4, &y = 0x22ccbc, diff = 2
*char1*&x = 0x22ccc4, &y = 0x22ccbc, diff = 2
*char2*&x = 0x22ccc4, &y = 0x22ccbc, diff = 2
*char3*&x = 0x22ccbc, &y = 0x22cc9c, diff = 8
*char4*&x = 0x22ccc4, &y = 0x22ccbc, diff = 2
*char5*&x = 0x22ccbc, &y = 0x22cc9c, diff = 8
*char6*&x = 0x22ccbc, &y = 0x22cc9c, diff = 8
*char7*&x = 0x22ccbc, &y = 0x22cc9c, diff = 8
*char8*&x = 0x22ccc4, &y = 0x22ccb4, diff = 4
*char9*&x = 0x22ccbc, &y = 0x22cc9c, diff = 8
*char10*&x = 0x22ccbc, &y = 0x22cc9c, diff = 8

Over to the linux server the output was a lot different with all the differences being the same.

long(x-y)
*char0*&x = 0x22ccc4, &y = 0x22ccbc, diff = 1
*char1*&x = 0x22ccc4, &y = 0x22ccbc, diff = 1
*char2*&x = 0x22ccc4, &y = 0x22ccbc, diff = 1
*char3*&x = 0x22ccbc, &y = 0x22cc9c, diff = 1
*char4*&x = 0x22ccc4, &y = 0x22ccbc, diff = 1
*char5*&x = 0x22ccbc, &y = 0x22cc9c, diff = 1
*char6*&x = 0x22ccbc, &y = 0x22cc9c, diff = 1
*char7*&x = 0x22ccbc, &y = 0x22cc9c, diff = 1
*char8*&x = 0x22ccc4, &y = 0x22ccb4, diff = 1
*char9*&x = 0x22ccbc, &y = 0x22cc9c, diff = 1
*char10*&x = 0x22ccbc, &y = 0x22cc9c, diff = 1

In Lab2 I was presented with many errors but mostly minor ones. Some of them which the lecturer said was ok as we are only experimenting.