SE250:lab-1:twon069

From Marks Wiki
Revision as of 05:18, 3 November 2008 by Mark (Sọ̀rọ̀ | contribs) (5 revision(s))
(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)
Jump to navigation Jump to search

Intro

To obtain the time required for computer to run an addition on different type of values such as short, long, double, float, integer.

Codes

#include <stdio.h>
#include <time.h>

int main()
{

	short total = 0;
	long t;

	t = clock();

	for (long i = 0; i<1000000000; i++) {
		total++;
	}

	t = (clock() - t);
	//printf("%ld\n", total);
	printf("%ld /%ld\n", t, CLOCKS_PER_SEC);

	return 0;
}

Result

int - 2.192sec

double - 8.262sec

float - 8.629sec

long - 2.404sec

short - 2.583sec


Summary

The following problem was encountered:

  • 1: Had no idea of how to use the function clock(), so went on google to search for appropriate use of the function. The outcome were that clock() returns a value in "ticks", of how long the program being started for, every time it is called and assigned to a value.
  • 2: After playing around with clock(), it always returns a value of 0, I realized the ammount of addition has to be enlarged in order to obtain more accurate and measurable value of clock(), so the loop were changed to be done 1billion times.
  • 3: The loops and defining t as clock() took time as well within the program, so the outcome of the result cannot be accurate, as the time taken to run through the loop was counted for. However the a comparative outcome can be drawn, as double and float takes a longer time to add than int, long and short.