https://wiki.kram.nz/index.php?action=history&feed=atom&title=Talk%3AENGSCI213%3AProbabilityTalk:ENGSCI213:Probability - Revision history2026-04-29T06:52:51ZRevision history for this page on the wikiMediaWiki 1.45.3https://wiki.kram.nz/index.php?title=Talk:ENGSCI213:Probability&diff=13720&oldid=prevMark: 2 revision(s)2008-11-03T10:43:34Z<p>2 revision(s)</p>
<p><b>New page</b></p><div>Question about the card problem: How come you've used permutations and not combinations? Is a hand of A, Q, 5 not the same as the hand 5, A, Q ?<br />
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== hey sam ==<br />
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I didn't see this page until today. I was only looking at the article page =p. Yeah ummm I don't know why I used permutations either lol. I think it was because when I was doing the number of ways of choosing 2 kinds and a Ace... I started off going:<br />
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<pre><br />
4 * 3 * 4 * 44 * 43 * ...<br />
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Because for a king we have 4 choices, then only 3 kings left. Then 4 choices for the ace. Then 52-8 = 44 choices for the next, 43 for the next and so on until we have 13 cards.<br />
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I think I assumed that these permutations will cancel out. As in, the repeats won't make a difference when you divide them, so using combinations will give the same answer... Well thats what I thought<br />
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[[User:Rwan064|Rwan064]] 15:15, 9 June 2008 (NZST)</div>Mark